/**
 * 344. 反转字符串
 *
 * 【简单】
 *
 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
 *
 * 示例 1：
 * 输入：s = ["h","e","l","l","o"]
 * 输出：["o","l","l","e","h"]
 *
 * 示例 2：
 * 输入：s = ["H","a","n","n","a","h"]
 * 输出：["h","a","n","n","a","H"]
 */

/**
 * Do not return anything, modify s in-place instead.
 */
function reverseString(s: string[]): void {
	let left = 0,
		right = s.length - 1
	while (left <= right) {
		;[s[left], s[right]] = [s[right], s[left]]

		left++
		right--
	}
}
